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(=0 41.1 %). !515AB>8<>ABL 2K?>;=5==KE @01>B C25;8G8;0AL <5=LH8<8 B5<?0<8  =0 77.4 % ?> A@02=5=8N A 2004 3>4>< 8 =0 34.0 % ?> A@02=5=8N A 2005 3>4><. ><<5@G5A:85 @0AE>4K 2 2006 3>4C C25;8G8;8AL ?> A@02=5=8N A C@>2=5< ?@>H;>3> 3>40 =0 36.0 %, 2 01A>;NB=>< 2K@065=88 C25;8G5=85 A>AB02;O5B 8463 BKA. @C1. #?@02;5=G5A:85 @0AE>4K B0:65 C25;8G8;8AL ?> A@02=5=8N A ?@>H;K< 3>4><  =0 32.9 %, 8;8 =0 3640 BKA.@C1. @81K;L >B ?@>406 2 2006 3 ?> A@02=5=8N A 2004 3 C25;8G8;0AL =0 15886, 8;8 2 8 @07. > A@02=5=8N A ?@>H;K< 3>4>< ?>:070B5;L C25;8G8;AO =0 12018 BKA.@C1., 8;8 ?>GB8 2 B@8 @070. @>F5=BK : ?>;CG5=8N 2 B5G5=85 8AA;54C5<>3> ?5@8>40 C25;8G8;8AL =0 894.0 %, 2 01A>;NB=>< 2K@065=88 C25;8G5=85 A>AB02;O5B 1070 BKA.@C1. @>F5=BK : C?;0B5 A=878;8AL =0 63 BKA.@C1., 8;8 =0 10.6 %. "01;8F0 3.2 8=0<8:0 8 A>AB02 D8=0=A>2KE @57C;LB0B>2  ;LD0 BKA.@C1. & & .. 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"0: :0: 2K@CG:0  ;LD0 - MB> ?@>872545=85 :>;8G5AB20 8 F5=K 2K?>;=5==KE @01>B, B> A=0G0;0 @0AAG8B05< 2;8O=85 =0 ?@81K;L >B ?@>406 F5=K, ?> :>B>@>9 2K?>;=O;8AL @01>BK, 0 70B5< @0AAG8B05< 2;8O=85 =0 ?@81K;L 87<5=5=8O :>;8G5AB20 548=8F ?@>40==KE @01>B. 0AAG8B05< 8=45:A 87<5=5=8O F5= =0 @01>BK  ;LD0 (JF) A CG5B>< A@54=53> ?>2KH5=8O F5= =0 @01>BK 2 B5G5=85 3>40 15 %: JF = (100 %  & %) / 100 % (2.1) 345  &%  ?@8@>AB (A=865=85) F5=K =0 ?@>4C:F8N 70 0=0;878@C5<K9 ?5@8>4 (2 %). JF 2006 3. = (100 % + 15 %) / 100 % = 1.15 !;54>20B5;L=>, 2K@CG:0  ;LD0 >B 2K?>;=5==KE @01>B 2 >BG5B=>< ?5@8>45 (2006 3>4) 2 A>?>AB028<KE F5=0E 1C45B @02=0: ' = 1 / JF, (2.2) 345 ' - 2K@CG:0 >B ?@>4068 2 A>?>AB028<KE F5=0E; 1 - 2K@CG:0 > ?@>4068 ?@>4C:F88 2 >BG5B=>< ?5@8>45; JF - 8=45:A F5=K. ' 2006 3. = 205054 BKA. @C1. : 1.15 = 178308 BKA.@C1. ;8O=85 =0 2K@CG:C  ;LD0 87<5=5=8O F5= @0AAG8BK205BAO ?> D>@<C;5:   F = 1  (1 : JF) = 1 - ' (2.3)   F = 205054 BKA. @C1. - 178308 BKA.@C1. = + 26746 BKA. @C1. 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